SOLUTION: Right the equation of the circle with a diameter having 2 end points (18,-3) , (4,3)

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Question 1075139: Right the equation of the circle with a diameter having 2 end points (18,-3) , (4,3)
Found 3 solutions by josgarithmetic, MathTherapy, ikleyn:
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
system%28Center%2Cx=%2818%2B4%29%2F2=11%2Cy=%28-3%2B3%29%2F2=0%29

Square of radius,%2818-4%29%5E2%2B%28-3-3%29%5E2=cross%28196%2B36=232%29

Equation: cross%28%28x-11%29%5E2%2By%5E2=232%29

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
Right the equation of the circle with a diameter having 2 end points (18,-3) , (4,3)
Correct answer: highlight_green%28%28x+-+11%29%5E2+%2B+y%5E2+=+58%29

As usual, IGNORE all other INCORRECT, RIDICULOUS, and NONSENSICAL responses.

Answer by ikleyn(52799) About Me  (Show Source):
You can put this solution on YOUR website!
.
highlight%28cross%28Right%29%29 Write the equation of the circle with a diameter having 2 end points (18,-3) , (4,3)
~~~~~~~~~~~~~~~~~~~~~ 

The center is  %28x%5B1%5D%2Bx%5B2%5D%29%2F2 = %2818%2B4%29%2F2 = 22%2F2 = 11,

               %28y%5B1%5D%2By%5B2%5D%29%2F2 = %28%28-3%29+%2B+3%29%2F2 = 0%2F2 = 0.


The center is (x,y) = (11,0).


The radius is sqrt%28%2818-11%29%5E2+%2B+%283-0%29%5E2%29 = sqrt%287%5E2+%2B+3%5E2%29 = sqrt%2849%2B9%29 = sqrt%2858%29.


The equation of the circle is 

%28x-11%29%5E2+%2B+y%5E2%29 = 58.