SOLUTION: what is the vertices of hyperbola 36y^2-49x^2=196

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Question 1073987: what is the vertices of hyperbola 36y^2-49x^2=196
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
%286%2F14%29%5E2%2Ay%5E2-%287%2F14%29%5E2x%5E2=1

%286%2F14%29%5E2%2Ay%5E2=1

y%5E2=%2814%2F6%29%5E2

y=0%2B-+14%2F6

y=0%2B-+7%2F3

VERTICES: (0, -7/3), (0, 7/3)