SOLUTION: Conic Sections II. Rewrite in standard form and graph. Find the vertex and all intercepts if any. y=−x2+6x−5

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Conic Sections II. Rewrite in standard form and graph. Find the vertex and all intercepts if any. y=−x2+6x−5      Log On


   

Question 1072638: Conic Sections II. Rewrite in standard form and graph. Find the vertex and all intercepts if any.
y=−x2+6x−5
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
y=-x%5E2%2B6x-5
y=-%28x%5E2-6x%2B5%29
y=-%28x%5E2-6x%2B9-9%2B5%29
y=-%28%28x-3%29%5E2-4%29
highlight%28y=-%28x-3%29%5E2%2B4%29--------standard form
--
Vertex: (3,4)


-%28x-3%29%5E2=-4
%28x-3%29%5E2=4
x-3=0%2B-+2
x=3%2B-+2
highlight%28system%28ZEROS%2Cx=1%2CAND%2Cx=5%29%29

y=-0%5E2%2B6%2A0-5
y=-5
y-intercept: (0,-5)

graph%28300%2C300%2C-6%2C6%2C-6%2C6%2C-x%5E2%2B6x-5%29