SOLUTION: Write the equation of a hyperbola with vertices at (-3, 0) and (3, 0) and co-vertices (0, 5) and (0, -5).

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Question 1068144: Write the equation of a hyperbola with vertices at (-3, 0) and (3, 0) and co-vertices (0, 5) and (0, -5).
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
The center of a hyperbola (or of an ellipse) is the midpoint of the segment connecting the vertices.
In this case, the center is the point halfway between (-3,0) and (3,0) .
That center is point (0,0), the origin.
Hyperbolas centered at the origin have the simplest equations.
They are equations of the form
x%5E2%2Fa%5E2-y%5E2%2Fb%5E2=1 or y%5E2%2Fa%5E2-a%5E2%2Fb%5E2=1 .
The term with a%5E2 in the denominator cannot be zero.
It has to be at least 1 .
For example, in x%5E2%2Fa%5E2-y%5E2%2Fb%5E2=1 , it must be true that x%5E2%2Fa%5E2%3E=1 ,
so it must be true that x%5E2%3E=a <---> system%28x%3E=a%2C%22or%22%2Cx%3C=-a%29 ,
and that makes (-a,0) and (a,0) the vertices.
The points (0,-b) and (0,b), which are not part of the hyperbola, are called the co-vertices.
The hyperbola in this problem is exactly that kind of hyperbola, with system%28a=3%2Cb=5%29 ,
and equation
highlight%28x%5E2%2F3%5E2-y%5E2%2F5%5E2=1%29 or highlight%28x%5E2%2F9-y%5E2%2F25=1%29 .