SOLUTION: Write the equation of the ellipse in standard form that satisfies the given conditions. Draw the ellipse, its focus, and directrix. 1.) The center is at (2,4), a vertex is at (-

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Write the equation of the ellipse in standard form that satisfies the given conditions. Draw the ellipse, its focus, and directrix. 1.) The center is at (2,4), a vertex is at (-      Log On


   



Question 1044355: Write the equation of the ellipse in standard form that satisfies the given conditions. Draw the ellipse, its focus, and directrix.
1.) The center is at (2,4), a vertex is at (-11,4), and the length of the minor axis is 24.
*Please help me solve this :( It would really mean so much to me. I badly need help in Math.

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
the equation of the ellipse in standard form is:
%28x-h%29%5E2%2Fa%5E2%2B%28y-k%29%5E2%2Fb%5E2=1
(h,k) coordinates of the center
if the center is at (2,4), means h=2 and k=4 and so far you have
%28x-2%29%5E2%2Fa%5E2%2B%28y-4%29%5E2%2Fb%5E2=1
if the length of the minor axis is 24, and we know that the semi-minor axis is half of the minor axis, so
b=24%2F2=12
The points where the major axis touches the ellipse are the "vertices" of the ellipse. The point midway between the two sticks is the "center" of the ellipse, and if a vertex is at (-11,4), center is at (2,4), distance from -11 to 2 is 13, than
a=13
substitute a and b
%28x-2%29%5E2%2F13%5E2%2B%28y-4%29%5E2%2F12%5E2=1 -> your answer