SOLUTION: Determine the vertex,focus,directrix,and axis of symmetry of the parabola with the given equation.
1) y^2-5x+12y=-16
2) 5x^2+30x+24y=51
guys,i really need your help on thi
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-> SOLUTION: Determine the vertex,focus,directrix,and axis of symmetry of the parabola with the given equation.
1) y^2-5x+12y=-16
2) 5x^2+30x+24y=51
guys,i really need your help on thi
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Question 1041166: Determine the vertex,focus,directrix,and axis of symmetry of the parabola with the given equation.
1) y^2-5x+12y=-16
2) 5x^2+30x+24y=51
guys,i really need your help on this. thanks :) Found 2 solutions by solver91311, josgarithmetic:Answer by solver91311(24713) (Show Source):
Complete the square on and rearrange into standard conics form:
Where is the vertex and is the distance from the vertex to the focus and from the vertex to the directrix. The term is squared so this parabola has a horizontal axis of symmetry and a vertical directrix.
Hence, vertex at , so , directrix at , focus , and axis of symmetry
You can do your own arithmetic to simplify the expressions for the directrix and the focus.
.
John
My calculator said it, I believe it, that settles it
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