SOLUTION: Find the coordinates, latus rectum and end points of the parabola x^2-8y=0 given the focus of (0,-3) and directrix y-4=0

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Question 1039964: Find the coordinates, latus rectum and end points of the parabola x^2-8y=0 given the focus of (0,-3) and directrix y-4=0
Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
General Form, y=%281%2F8%29x%5E2
Standard Form, y=%281%2F8%29%28x-0%29%5E2%2B0
Latus Rectum depends on knowing the focus, which is given as (0,-3).

The vertex is read from the standard form equation, and is (0,0), the Origin. The directrix is the line y=4, a horizontal line. Your given parabola with its vertex on the Origin, is concave upward, and the focus must be on the concave region of the parabola's cartesian system.

Using your equation or the standard form of it, and the known vertex and directrix, the focus must be 4 units away from (0,0) in the opposite direction of the directrix (x,4), putting the focus at (0,-4). This contradicts your given parabola based on its equation.

Here is what your parabola according to your given equation and the given directrix look like:
graph%28300%2C300%2C-6%2C6%2C-6%2C6%2Cy=x%5E2%2F8%2C4%29

SOME OF YOUR GIVEN INFORMATION OR DESCRIPTION IS WRONG.