SOLUTION: Find the vertices, the endpoints of the minor axis, and the foci of the given ellipse. 10x2 + 80x + 7y2 + 42y + 83 = 0

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Question 1033118: Find the vertices, the endpoints of the minor axis, and the foci of the given ellipse.
10x2 + 80x + 7y2 + 42y + 83 = 0

Found 2 solutions by robertb, ikleyn:
Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
10x%5E2+%2B+80x+%2B+7y%5E2+%2B+42y+%2B+83+=+0+
<==> 10%28x%5E2%2B8x%2B16%29%2B7%28y%5E2%2B6y%2B9%29+=+-83%2B160%2B63
==> 10%28x%2B4%29%5E2%2B7%28y%2B3%29%5E2+=+140
==> %28x%2B4%29%5E2%2F14%2B%28y%2B3%29%5E2%2F20+=+1
==> the center of the ellipse is the point (-4,-3).
Now a%5E2+=+20 and b%5E2+=+14 ==> c%5E2+=+20-14+=+6, because for any ellipse, a%5E2+=+b%5E2%2Bc%5E2.
(Also the major axis is parallel to the y-axis, while the minor axis is parallel to the x-axis.)
==> the vertices are (-4, -3%2B2sqrt%285%29) and (-4, -3-2sqrt%285%29),
the co-vertices are (-4%2Bsqrt%2814%29,-3) and (-4-sqrt%2814%29,-3),
while the foci are (-4, -3%2Bsqrt%286%29) and (-4, -3-sqrt%286%29).

Answer by ikleyn(52797) About Me  (Show Source):
You can put this solution on YOUR website!
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Figure. Ellipse %28x%2B4%29%5E2%2F14 + %28y%2B3%29%5E2%2F20 = 1