SOLUTION: 13x^2+3y^2=39 Need focus of the given ellipse smaller y value? larger y value?

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: 13x^2+3y^2=39 Need focus of the given ellipse smaller y value? larger y value?      Log On


   

Question 1032832: 13x^2+3y^2=39
Need focus of the given ellipse
smaller y value?
larger y value?
Answer by fractalier(6550) About Me  (Show Source):
You can put this solution on YOUR website!
From
13x%5E2%2B3y%5E2=39
we divide by 39 and get
x%5E2%2F3+%2B+y%5E2%2F13+=+1
This is a "tall" ellipse.
c^2 = 13 - 3 = 10
so that the foci are at
(0, sqrt(10)) and (0, -sqrt(10))