SOLUTION: Help, Please! I am supposed to write a conic equation in STANDARD FORM for a circle centered 3 units below the origin with radius 4 sqrt(3). I have the equation (x-0)^2 +(y+3)^2

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Help, Please! I am supposed to write a conic equation in STANDARD FORM for a circle centered 3 units below the origin with radius 4 sqrt(3). I have the equation (x-0)^2 +(y+3)^2       Log On


   

Question 1028771: Help, Please! I am supposed to write a conic equation in STANDARD FORM for a circle centered 3 units below the origin with radius 4 sqrt(3). I have the equation (x-0)^2 +(y+3)^2 = (4 sqrt(3))^2. Now, is this the STANDARD FORM or should I break it down to x^2+y^2+6y+9=48?? Confused on which is standard form? Thank you!
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
Standard form for a circle: %28x-h%29%5E2%2B%28y-k%29%5E2=r%5E2

General form for a circle: Ax%5E2%2BBy%5E2%2BCx%2BDy=E and must include A=B.