SOLUTION: How would you put 2x^2+8y-20=0 in standard form?

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Question 1028093: How would you put 2x^2+8y-20=0 in standard form?
Answer by fractalier(6550) About Me  (Show Source):
You can put this solution on YOUR website!
2x^2 + 8y - 20 = 0
8y = -2x^2 + 20
y = (-1/4)x^2 + 5/2