SOLUTION: Write the standard equation for each circle. Then state the coordinates of its center and give its radius. X^2+ y^-10x-16y+88=0 and x^2+y^2+22x-2y=-120

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Write the standard equation for each circle. Then state the coordinates of its center and give its radius. X^2+ y^-10x-16y+88=0 and x^2+y^2+22x-2y=-120      Log On


   

Question 1019918: Write the standard equation for each circle. Then state the coordinates of its center and give its radius. X^2+ y^-10x-16y+88=0 and x^2+y^2+22x-2y=-120
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


I presume you mean because ^ is not the equation of a circle. In the first place and are two different variables and you are either raising y to the 0 power or to the -10x power the way you wrote the equation.

Presuming



Then rearrange:



Complete the square on and :



Factor the two perfect square trinomials and combine terms in the RHS:



Any equation of the form



Is the equation of a circle centered at with radius , so you can read your center and radius directly from the re-formed equation.

John

My calculator said it, I believe it, that settles it