SOLUTION: I found the locus of a question to be x^2 - 16x +y^2 +4y +28 = 0.
I need help with this part: What point on the straight line joining the points (-4,2) and (5,-1) is on the locu
Algebra ->
Quadratic-relations-and-conic-sections
-> SOLUTION: I found the locus of a question to be x^2 - 16x +y^2 +4y +28 = 0.
I need help with this part: What point on the straight line joining the points (-4,2) and (5,-1) is on the locu
Log On
Question 1011856: I found the locus of a question to be x^2 - 16x +y^2 +4y +28 = 0.
I need help with this part: What point on the straight line joining the points (-4,2) and (5,-1) is on the locus. Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! I found the locus of a question to be x^2 - 16x +y^2 +4y +28 = 0.
I need help with this part: What point on the straight line joining the points (-4,2) and (5,-1) is on the locus
---------------
Find the equation of the line thru the 2 points. Solve it for y.
Sub for y in the circle's equation.
etc
