SOLUTION: write the equation of a hyperbola with vertices at (3,-1) and (3,-9) and co-vertices at (-6,-5) and (12,-5)

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Question 1011162: write the equation of a hyperbola with vertices at (3,-1) and (3,-9) and co-vertices at (-6,-5) and (12,-5)
Answer by MathLover1(20850) About Me  (Show Source):
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write the equation of a hyperbola with vertices at (3,-1) and (3,-9) and co-vertices at (-6,-5) and (12,-5)
since (3,-1) and (3,-9) are vertically aligned (they have the same x-coordinates), so the hyperbola is vertical.
Equation of a vertical hyperbola:
%28y-k%29%5E2%2Fa%5E2-+%28x-h%29%5E2%2Fb%5E2=+1
with
 center (h,k)
 vertices (h,k±a)
 co-vertices (h±b,k)
 foci (h,k±c), c%5E2+=+a%5E2%2Bb%5E2
Apply your data.
The center is midway between the vertices, at (3,-5).
h+=+3
k+=+-5
vertices (3,-5±a) = (3,-1) and (3,-9)
-5%2Ba=-1
a+=+4
co-vertices (3±b,-5) = (-6,-5) and (12,-5)
b+=+9
%28y%2B5%29%5E2%2F4%5E2+-+%28x-3%29%5E2%2F9%5E2+=+1