SOLUTION: How far from the y-axis is the center of the curve 2x2 + 2y2 + 10x – 6y – 55 = 0?

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: How far from the y-axis is the center of the curve 2x2 + 2y2 + 10x – 6y – 55 = 0?      Log On


   



Question 1009440: How far from the y-axis is the center of the curve
2x2 + 2y2 + 10x – 6y – 55 = 0?

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Complete the square to find the center of the circle,
2x%5E2+%2B+2y%5E2+%2B+10x+%96+6y+%96+55+=+0
2x%5E2%2B10x%2B2y%5E2-6y-55=0
x%5E2%2B5x%2By%5E2-3y-55%2F2=0
%28x%5E2%2B5x%2B25%2F4%29%2B%28y%5E2-3y%2B9%2F4%29-55%2F2-25%2F4-9%2F4=0
%28x%2B5%2F2%29%5E2%2B%28y-3%2F2%29%5E2=110%2F4%2B25%2F4%2B9%2F4
%28x%2B5%2F2%29%5E2%2B%28y-3%2F2%29%5E2=144%2F4
%28x%2B5%2F2%29%5E2%2B%28y-3%2F2%29%5E2=36
The circle is centered at (-5%2F2,3%2F2) so it is 5%2F2 from the y-axis.