SOLUTION: Please help me answer this equation: Identify the vertex, focus,and directrix of equation: y=1/12x^2

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Question 984896: Please help me answer this equation:
Identify the vertex, focus,and directrix of equation:
y=1/12x^2
Found 2 solutions by josgarithmetic, macston:
Answer by josgarithmetic(39621) About Me  (Show Source):
You can put this solution on YOUR website!
This should help to make everything clear about what you ask:
Deriving Equation for Parabola

Your parabola has its vertex as a minimum, and parabola opens upward.

Answer by macston(5194) About Me  (Show Source):
You can put this solution on YOUR website!
.
4p%28y-k%29=%28x-h%29%5E2
where (h,k) is the vertex and p is distance from vertex to focus
.
Given equation:
y=x%5E2
4%281%2F4%29%28y-0%29=%28x-0%29%5E2
So vertex=(h,k)=(0,0)
Focus is at p from vertex, +1/4 from vertex=(0,1/4)
Directrix is -p from vertex, y=-(1/4)
.
+graph%28+800%2C+800%2C+-10%2C+10%2C+-10%2C+10%2C++x%5E2%2F12%29+