SOLUTION: How do I put 10(y+3)^2-(x-4)^2=80 into a standard form for a hyperbola?

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Question 967145: How do I put 10(y+3)^2-(x-4)^2=80 into a standard form for a hyperbola?
Found 2 solutions by josgarithmetic, MathLover1:
Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
Learn to know what the standard form hyperbola format is.

%28y-k%29%5E2%2Fa%5E2-%28x-h%29%5E2%2Fb%5E2=1

Your steps to take should be very predictable. What do you do to both sides so that the right side member is 1?

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
you have
10%28y%2B3%29%5E2-%28x-4%29%5E2=80+
and you want to obtain:
%28x+-+h%29%5E2%2Fa%5E2+-+%28y+-+k%29%5E2%2Fb%5E2+=+1

both sides divide by 80

10%28y%2B3%29%5E2%2F80-%28x-4%29%5E2%2F80=80%2F80+

cross%2810%29%28y%2B3%29%5E2%2Fcross%2880%298-%28x-4%29%5E2%2F80-1+

%28y%2B3%29%5E2%2F8-%28x-4%29%5E2%2F80=1+