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Question 916931: Please help with this problem:
Circle one: f(x)=6x^2-36x+59 has {zero, one or two} roots.
Can you please show me how you got the answer
Thank you.
Answer by jim_thompson5910(35256)   (Show Source):
You can put this solution on YOUR website! From f(x)=6x^2-36x+59, we see that a = 6, b = -36 and c = 59
This is because the general form is f(x) = ax^2 + bx + c
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Use the discriminant formula D = b^2 - 4ac
D = b^2 - 4ac
D = (-36)^2 - 4(6)(59) ... plug in a = 6, b = -36 and c = 59
D = -120
The discriminant is negative, so there are zero real solutions.
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