SOLUTION: find the vertices and foci of the ellipse 3x^2+4y^2=12

Question 893103: find the vertices and foci of the ellipse
3x^2+4y^2=12

Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
find the vertices and foci of the ellipse
3x^2+4y^2=12

This is an equation of an ellipse with horizontal major axis and center at the origin
Its standard form of equation:
center:(0,0)
a^2=4
a=2
vertices: (0�a,0)=(0�2,0)+(-2,0) and (2,0)
..
b^2=3
c^2=a^2-b^2=4-3=1
c=1
foci: (0�c,0)=(0�1,0)+(-1,0) and (1,0)
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