SOLUTION: Find the vertex, focus and directrix of the parabola and sketch the graph 4x-y^2=0

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Question 879876: Find the vertex, focus and directrix of the parabola and sketch the graph
4x-y^2=0
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Handling this question might be easier using the already derived equation for the simpler model of x=y^2. Taking this simple form as 4x=y^2 to get directrix and focus depends on knowing how the equation was formed from knowing directrix and focus.

4px=y%5E2 is an equation of a parabola with p being distance from vertex to directrix and distance from vertex to focus. Your given equation is 4%2A1%2Ax=y%5E2. The parabola is horizontal with a vertex (0,0). Focus is (0,1) and directrix is x=-1.