SOLUTION: Find the vertex of the parabola, the direction it opens, and the axis of symmetry. y = {{{4(x + 4)^2 + 6}}}

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Find the vertex of the parabola, the direction it opens, and the axis of symmetry. y = {{{4(x + 4)^2 + 6}}}      Log On


   

Question 876477: Find the vertex of the parabola, the direction it opens, and the axis of symmetry.
y = 4%28x+%2B+4%29%5E2+%2B+6
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
The equation for this parabola is in standard form.

y=a%28x-h%29%5E2%2Bk
Vertex is (h,k)
Axis of Symmetry is x=h
Parabola opens down for a%3C0, or opens up for a%3E0.