SOLUTION: Find the vertex of the parabola, and the direction it opens. {{{3x^2 - 12x - y + 18 = 0}}}

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Find the vertex of the parabola, and the direction it opens. {{{3x^2 - 12x - y + 18 = 0}}}       Log On


   

Question 876466: Find the vertex of the parabola, and the direction it opens.
3x%5E2+-+12x+-+y+%2B+18+=+0

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Complete the square to get to vertex form,
3x%5E2+-+12x+-+y+%2B+18+=+0
y=3x%5E2-12x%2B+18
y=3%28x%5E2-4x%29%2B+18
y=3%28x%5E2-4x%2B4%29%2B+18-3%2A4
y=3%28x-2%29%5E2%2B6
(3,6)
Since 3%3E0, parabola opens up.
graph%28300%2C300%2C-2%2C10%2C-2%2C10%2C3%28x-2%29%5E2%2B6%29