SOLUTION: A parabola has a Vertex of V=(6,4) and a focus of F=(6,-1).
What is the equation?
(x-h)^2=4p(y-k) or (y-k)^2=4p(x-h)
Hint: determine the 4p value
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-> SOLUTION: A parabola has a Vertex of V=(6,4) and a focus of F=(6,-1).
What is the equation?
(x-h)^2=4p(y-k) or (y-k)^2=4p(x-h)
Hint: determine the 4p value
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Question 875540: A parabola has a Vertex of V=(6,4) and a focus of F=(6,-1).
What is the equation?
(x-h)^2=4p(y-k) or (y-k)^2=4p(x-h)
Hint: determine the 4p value Answer by ewatrrr(24785) (Show Source):
You can put this solution on YOUR website! V=(6,4) and a focus of F=(6,-1), Parabola opening down along x = 6
p = -5. 4p = -20
y = -1/20(x - 6)^2 + 4
