SOLUTION: 4x^2+y^2+40x+96=0

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Question 874817: 4x^2+y^2+40x+96=0
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
4x^2+y^2+40x+96=0
4(x -5)^2 - 100 + y^2 + 96 = 0
4(x -5)^2 + y^2 = 4
(x -5)^2/1^2 + y^2/2^2 = 0 Ellipse C(5,0), major axis along x = 5