SOLUTION: Write the equation in standard form for the hyperbola with center (5, 0), co-vertex (6, 0), and focus (5, radical 37) How do you work backwards on this??

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Write the equation in standard form for the hyperbola with center (5, 0), co-vertex (6, 0), and focus (5, radical 37) How do you work backwards on this??      Log On


   



Question 774474: Write the equation in standard form for the hyperbola with center (5, 0), co-vertex (6, 0), and focus (5, radical 37)
How do you work backwards on this??

Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Write the equation in standard form for the hyperbola with center (5, 0), co-vertex (6, 0), and focus (5, radical 37)
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Given hyperbola has a vertical transverse axis(gleaned from given focus coordinates)
Its standard form of equation: %28y-k%29%5E2%2Fa%5E2-%28x-h%29%5E2%2Fb%5E2=1, (h,k)=(x,y) coordinates of center
center:(5,0)
b=6 (co-vertex)
b^2=36
c=√37 (focus)
c^2=37
c^2=a^2+b^2
a^2=c^2-b^2=37-36=1
Equation:
y%5E2-%28x-5%29%5E2%2F36=1