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Question 759640: Compared to the focus and directrix of y = ax^2, explain how the focus and directrix of
(y-k) = a(x-h)^2 are affected by the values of h and k.
Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Compared to the focus and directrix of y = ax^2, explain how the focus and directrix of
(y-k) = a(x-h)^2 are affected by the values of h and k.
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x^2 = ay
4p = a
p = a/4
Focus:: (0,a/4)
Directris: y = -a/4
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y-k = a(x-h)^2
Focus:: (0+h,(a/4)+k)
Directrix: y = (-a/4)+k
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Cheers,
Stan H.
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