SOLUTION: Determine an equation for the hyperbola . Foci at (12,0) (-12,0) and transverse axis of length 18

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Question 747546: Determine an equation for the hyperbola .
Foci at (12,0) (-12,0) and transverse axis of length 18
Answer by lwsshak3(11628) About Me  (Show Source):
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Determine an equation for the hyperbola .
Foci at (12,0) (-12,0) and transverse axis of length 18
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Hyperbola has a horizontal transverse axis.
Its standard form of equation: %28x-h%29%5E2%2Fa%5E2-%28y-k%29%5E2%2Fb%5E2=1, (h,k)=(x,y) coordinates of center.
..
center: (0,0)
Given length of horizontal transverse axis=18=2a
a=9
a^2=81
c=12 (distance from center to foci on the transverse axis)
c^2=144
c^2=a^2+b^2
b^2=c^2-a^2=144-81=63
Equation of given hyperbola: x%5E2%2F81-y%5E2%2F63=1