SOLUTION: Sketch the graph of a parabola and give the vertex, focal point, and directrix. A) x^2-6x-3y+3=0 B) 3x^2-12x+2y-10=0

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Sketch the graph of a parabola and give the vertex, focal point, and directrix. A) x^2-6x-3y+3=0 B) 3x^2-12x+2y-10=0      Log On


   

Question 735645: Sketch the graph of a parabola and give the vertex, focal point, and directrix.
A) x^2-6x-3y+3=0
B) 3x^2-12x+2y-10=0
Answer by lynnlo(4176) About Me  (Show Source):
You can put this solution on YOUR website!
(A)X^2-6X-3Y+3=0
(3,-2)=======(3,-5/4)===========Y=-11
VERTEX=======FOCI==============DIRECTRIX
(B)3X^2-12X+2Y-10=0
(2,11)=======(2,65/6)==========Y=67/6
VERTEX======FOCI==============DIRECTRIX
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