|
Question 686184: Determine the vertex, focus and directrix of the parabola:
y^2-6x-8x=-17
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! Determine the vertex, focus and directrix of the parabola:
y^2-6x-8x=-17
y^2-14x=-17
y^2=14x-17
y^2=14(x-17/14)
This is a parabola that opens rightwards.
Its standard form of equation: (y-k)^2=4p(x-h), (h,k)=(x,y) coordinates of the vertex
For given parabola:
vertex: (17/14,0)
axis of symmetry: y=0 or x-axis
4p=14
p=14/4=7/2=49/14
focus: (66/14,0) (p distance to the right of vertex on the axis of symmetry)
directrix: y=-32/14 (p distance to the left of vertex on the axis of symmetry)
|
|
|
| |
