SOLUTION: which is the asymptotes of y^2/121-x^2/36=1 ?

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: which is the asymptotes of y^2/121-x^2/36=1 ?      Log On


   

Question 629072: which is the asymptotes of y^2/121-x^2/36=1 ?
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
which is the asymptotes of y^2/121-x^2/36=1
This is an equation of a hyperbola with vertical transverse axis.
Its standard form: %28y-k%29%5E2%2Fa%5E2-%28x-h%29%5E2%2Fb%5E2, (h,k)=(x,y) coordinates of center
Given equation: y%5E2%2F121-x%5E2%2F36=1
center: (0,0)
a^2=121
a=√121=11
b^2=36
b=√36=6
slopes of asymptotes for hyperbolas with vertical transverse axis=±a/b=±11/6
Asymptotes are equations of straight lines that go thru the center.
Their standard form: y=mx+b, m=slope, b=y-intercept
Since center is at (0,0), y-intercept for both asymptotes=0
Equations for asymptotes:
y=11x%2F6
and
y=-11x%2F6