SOLUTION: x^2/49-y^2/64=1 find the foci

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: x^2/49-y^2/64=1 find the foci      Log On


   



Question 628200: x^2/49-y^2/64=1
find the foci

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 
Hi,
Standard Form of an Equation of an Ellipse is %28x-h%29%5E2%2Fa%5E2+%2B+%28y-k%29%5E2%2Fb%5E2+=+1+
where Pt(h,k) is the center. (a variable positioned to correspond with major axis)
a and b are the respective vertices distances from center
and ±sqrt%28a%5E2-b%5E2%29are the foci distances from center: a > b
x%5E2%2F49-y%5E2%2F64=1 C(0,0) and f%5Bd%5D+=+sqrt%2864-49%29+=+sqrt%2815%29
foci are (0, ±sqrt%2815%29)