SOLUTION: what is the vertex and the y intercept of the graph function y = 2(x + 2)^2 - 2

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Question 623945: what is the vertex and the y intercept of the graph function y = 2(x + 2)^2 - 2
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 
Hi,
y = 2(x + 2)^2 - 2 V(-2,-2), Parabola opens UP, axis of symmetry x= -2,
and when x = 0 ⇒ y = 8-2 = 6

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the vertex form of a Parabola opening Up(a>0) or Down(a<0), highlight%28y%29=a%28x-h%29%5E2+%2Bk where(h,k) is the vertex and line of symmetry is x = h
The standard form is %28x+-h%29%5E2+=+4p%28y+-k%29, where the focus is (h,k + p)
the vertex form of a Parabola opening Right(a>0) or Left(a<0), highlight%28x%29=a%28y-k%29%5E2+%2Bh where(h,k) is the vertex and line of symmetry is y = k
The standard form is %28y+-k%29%5E2+=+4p%28x+-h%29, where the focus is (h +p,k )