SOLUTION: Find the standard form of the equation of the specified hyperbola. 49x^2 - 196x - 36y^2 + 504y - 3332 = 0

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Find the standard form of the equation of the specified hyperbola. 49x^2 - 196x - 36y^2 + 504y - 3332 = 0      Log On


   

Question 618960: Find the standard form of the equation of the specified hyperbola.
49x^2 - 196x - 36y^2 + 504y - 3332 = 0
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Find the standard form of the equation of the specified hyperbola.
49x^2 - 196x - 36y^2 + 504y - 3332 = 0
complete the square
49(x^2-4x+4)-36(y^2-14y+49)= 3332+196-1764
49(x-2)^2-36(y-7)^2=1764
divide by 1764
Equation of given hyperbola: (x-2)^2/36-(y-7)^2/49=1