SOLUTION: I need help solving for the polar equation of an ellipse when they give you the vertices (8,pi/2) & (16,3pi/2). what I'm having trouble with is solving for the center of the ell

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: I need help solving for the polar equation of an ellipse when they give you the vertices (8,pi/2) & (16,3pi/2). what I'm having trouble with is solving for the center of the ell      Log On


   



Question 556821: I need help solving for the polar equation of an ellipse when they give you the vertices (8,pi/2) & (16,3pi/2).
what I'm having trouble with is solving for the center of the ellipse,it would be a great help if you could explain that.

Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
as far as i can tell, your vertices are at (0,8) and (0,-16).
that makes the center of the ellipse halfway between them which would be at the point (0,-4).
a polar coordinate is of the form (r,T) where r is the length of the line segment and T is the angle.
pi/2 = 90 degrees which puts one of the points at (0,8).
3pi/2 = 270 degrees which puts the other point at (0,-16).
the point halfway between (0,8) and (0,-16) is the point (0,-4).
that's what i think anyway.