You can put this solution on YOUR website! Identify the vertex for graph of y=4(x+3)^2+4
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Standard form of equation for a parabola that opens upwards: y=A(x-h)^2+k, (h,k)=(x,y) coordinates of the vertex. A is a multiplier which affects the slope or steepness of the curve.
For given equation, y=4(x+3)^2+4
vertex: (-3,4)