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Question 503166: find the vertex, the line of symmetry and the maximum or minimum value of f(x). Graph the function f(x)=.2(x+6)^2+1
the vertex is=
the line of symmetery is=
what is the man/min of f(x)=
is the value f(-6)=1, a min or max?
then graph that represents.
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! find the vertex, the line of symmetry and the maximum or minimum value of f(x). Graph the function f(x)=1/5(x+6)^2+1
the vertex is=
the line of symmetery is=
what is the man/min of f(x)=
is the value f(-6)=1, a min or max?
then graph that represents.
**
This is an equation of a parabola of the standard form: y=A(x-h)^2+k, with (h,k) being the (x,y) coordinates of the vertex. Because lead coefficient is positive, parabola opens upwards, that is, function has a minimum.
..
For given equation:
Vertex:(-6, 1)
Line of symmetry: x=-6
Minimum: 1
f(-6)=1 is a minimum
see graph below:
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