I'm pretty sure that trigonometry is needed for this problem, but I'm not totally sure!
The line 3y+x=10 intersects the circle x^2+y^2=50 in two distinct points. Suppose you drew a radius to each of the two points of intersection. Find the angle, in standard position, created by each radius.
Thank you!!!!
The other tutor's second angle is incorrect. It should be 135°.
He thought you wanted the angle between the two radii, not the
angles in standard position.
First we'll find the two points where the line intersects the
circle:
Solve the first equation for x
Substitute in the second equation:
Divide through by 10
Factor
Use zero factor property:
so
so
To find the x-value correponding to each of those,
substitute each y-value into
To find the x-value that corresponds to y=1
Therefore one point of intersecion is (7,1).
To find the x-value that corresponds to y=5
Therefore the other point of intersection is (5,-5).
We'll take each one separately:
Let's erase everything except the radius on the right:
Let's draw a perpendicular from the point (7,1) to the x-axis,
and label the angle Ꮎ, indicated by the red counterclockwise arc.
That's one answer.
Now let's erase everything except the radius on the leftt:
Let's draw a perpendicular from the point (7,1) to the x-axis,
and label the angle Ꮎ, indicated by the red counterclockwise arc.
So the reference angle for Ꮎ is 45° degrees.
And it's in the 2nd quadrant so we subtract from 180°
and get 180°-45° = 135°
So the second angle is
Edwin