SOLUTION: i need help with this write the standard form of the equation of the parable with its vertex at (0,0) and focus at (-2,0)

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Question 455843: i need help with this
write the standard form of the equation of the parable with its vertex at (0,0) and focus at (-2,0)

Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
write the standard form of the equation of the parabola with its vertex at (0,0) and focus at (-2,0)
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From given info, it can be seen that this is a parabola with a horizontal axis of symmetry, y=0 or x-axis, and it opens leftward. You can tell it has a horizontal axis of symmetry because the y-coordinates of the focus and vertex are the same. It opens leftward because the focus is to the left of the vertex. Because it opens leftwards, the function has a negative sign.
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Standard form of given parabola:
(y-k)^2=-4p(x-h)
(y-0)^2=-4p(x-0)
y^2=-4px
p=distance between vertex and focus on the axis of symmetry=2
4p=8
Equation: y^2=-8x
See the graph below as a visual check on the answer.
y=(-8x)^.5
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+graph%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2C%28-8x%29%5E.5%2C-%28-8x%29%5E.5%29+