Question 448807: Write an equation in standard form for the conic section.
Hyperbola with vertices (4,3) and (2,3) and foci at (0,3) and (6,3)
Answer by ewatrrr(24785)   (Show Source):
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Hi
Hyperbola with vertices (4,3) and (2,3) and foci at (0,3) and (6,3)
Opens right and left C(3,3) a = 1
(x-3)^/1 - (y-3)^2/b^2 =1
foci at (0,3) and (6,3) c =  = 3, b^2 = 8
Standard Form of an Equation of a Circle is 
where Pt(h,k) is the center and r is the radius
Standard Form of an Equation of an Ellipse is 
where Pt(h,k) is the center and a and b are the respective vertices distances from center.
Standard Form of an Equation of an Hyperbola is  where Pt(h,k) is a center with vertices 'a' units right and left of center.
Standard Form of an Equation of an Hyperbola opening up and down is:
 where Pt(h,k) is a center with vertices 'b' units up and down from center.
Using the vertex form of a parabola opening up or down, 
where(h,k) is the vertex
The standard form is  , where the focus is (h,k + p)
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