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Question 433131: Please help me solve this question.
Find the equation of the hyperbola centered at (2,-3), whose slopes of asymptotes are y=± 3 and which opens up and down.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Find the equation of the hyperbola centered at (2,-3), whose slopes of asymptotes are y=± 3 and which opens up and down.
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Form:
-[(x-h)^2/a^2]+[(y-k)^2/b^2] = 1
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-[(x-2)^2/b^2]+[(y+3)^2/a^2 = 1
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Asymptotes: y = 3x and y = -3x
Find a and b
a/b = 3
a = 3b
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Note: you need to know a or b to finish
the hyperbola equation form.
You can get a or b if you know one of the vertices.
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Cheers,
Stan H.
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