SOLUTION: The distance a car can travel on a certain amount of fuel varies inversely with its speed. If a car traveling 50 mph can travel 300 miles on 10 gallons of fuel, how far could the

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: The distance a car can travel on a certain amount of fuel varies inversely with its speed. If a car traveling 50 mph can travel 300 miles on 10 gallons of fuel, how far could the       Log On


   



Question 42120: The distance a car can travel on a certain amount of fuel varies inversely with its speed. If a car traveling 50 mph can travel 300 miles on 10 gallons of fuel, how far could the car travel on 10 gallons of fuel at 60 mph?
Thank you

Found 2 solutions by fractalier, psbhowmick:
Answer by fractalier(6550) About Me  (Show Source):
You can put this solution on YOUR website!
For an inverse relation such as this we have
d = kf / s
Now plug in to find k
300 = k(10) / 50
k = 1500
Now redo it with the new k
d = 1500f / s
Now plug in the new data to find d
d = 1500(10) / 60
d = 250 miles

Answer by psbhowmick(878) About Me  (Show Source):
You can put this solution on YOUR website!
Let car speed = 'v' mph and distance traveled = 's' miles.
[As the amount of fuel remains constant (= 10 gallons) so it will not come in any equation.]
As distance traveled varies inversely as the speed, so
s+=+k%2Fv________(1)
where k = constant of variation.

When v = 50, s = 300.
Put this in eqn.(1).
Thus we get
300=k%2F50
or k = 15000

So, putting the value of k eqn(1) becomes
s=15000%2Fv________(2)

When v = 60 from (2) we get
s=15000%2F60 = 250

The reqd. distance is 250 miles.