SOLUTION: I am working on parabola and i get the fundmentals but i am having alittle issue when doing this problem f(x)=-3(x-2)square+1 I have to find 2 points using square root property

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: I am working on parabola and i get the fundmentals but i am having alittle issue when doing this problem f(x)=-3(x-2)square+1 I have to find 2 points using square root property      Log On


   

Question 417649: I am working on parabola and i get the fundmentals but i am having alittle issue when doing this problem f(x)=-3(x-2)square+1
I have to find 2 points using square root property
Found 2 solutions by stanbon, MathLover1:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
f(x)=-3(x-2)^2+1
I have to find 2 points using square root property
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You have already completed the square.
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If x = 2 you get y = -3*0+1 = 1
If x = 3 you get y = -3*1+1 = -2
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Cheers,
Stan H.
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Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
f%28x%29=-3%28x-2%29%5E2%2B1
find 2 points

f%28x%29=-3%28x%5E2-4x%2B2%29%2B1

f%28x%29=-3x%5E2%2B12x-6%2B1
f%28x%29=-3x%5E2%2B12x-5
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+ .....a=-3}, b=12 and c=-5

x+=+%28-12+%2B-+sqrt%28+12%5E2-4%2A%28-3%29%2A%28-5%29+%29%29%2F2%2A%28-3%29+

x+=+%28-12+%2B-+sqrt%28+144+-60+%29%29%2F%28-6%29+


x+=+%28-12+%2B-+sqrt%28+84+%29%29%2F%28-6%29+


x1+=+%28-12+%2B-+9.2%29+%2F-6+


x1+=+%28-2.8%29+%2F-6+


x1+=+0.47...one x-intercept....point:(0.47,0)

x2+=+%28-12+-+9.2%29+%2F-6+


x2+=+%28-21.2%29+%2F-6+


x2+=+3.53...the other x-intercept....point:(3.53,0)



+graph%28+500%2C+500%2C+-10%2C+10%2C+-10%2C+10%2C+-3x%5E2%2B12x-5%29+