SOLUTION: What is the equation of a parabola with a vertex at (5,2) and a directrix y=1?

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Question 370311: What is the equation of a parabola with a vertex at (5,2) and a directrix y=1?
Answer by robertb(5830) About Me  (Show Source):
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The focus must be (5,3), and c = 1 (distance between the focus and vertex). Therefore the equation is 4%28y-2%29+=+%28x+-+5%29%5E2, or y+=+%281%2F4%29%2A%28x+-+5%29%5E2%2B2.