SOLUTION: Please help: I have to find the center and the length of a radius of the circle: X^2+Y^2-2x-8y+8=0 Thanks,

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Please help: I have to find the center and the length of a radius of the circle: X^2+Y^2-2x-8y+8=0 Thanks,      Log On


   

Question 32420: Please help:
I have to find the center and the length of a radius of the circle:
X^2+Y^2-2x-8y+8=0
Thanks,
Answer by mukhopadhyay(490) About Me  (Show Source):
You can put this solution on YOUR website!
x^2+y^2-2x-8y+8=0
=>(x-1)^2 + (y-4)^2 = 3^2
Center is at (1,4) and radius is 3