SOLUTION: I have to find the vertex, focus, which way it opens, the directrix, axis of symmetry, the length of LR, and the endpoints of LR. The equation is: (x+3)^2=10(y-4). So far I have tr

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: I have to find the vertex, focus, which way it opens, the directrix, axis of symmetry, the length of LR, and the endpoints of LR. The equation is: (x+3)^2=10(y-4). So far I have tr      Log On


   

Question 281139: I have to find the vertex, focus, which way it opens, the directrix, axis of symmetry, the length of LR, and the endpoints of LR. The equation is: (x+3)^2=10(y-4). So far I have tried and found the vertex is: (-3,4) and the focus is: (-3,2.5), it opens up, the directrix is y=-2.5, and the axis of symmetry is x=-3. But when I tried to graph it it didn't work out. Can you help me?
Thank you.
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
the vertex is -3,4
it does open up
the focus is NOT -3,2.5 but -3, 6.5
the directrix is NOT y=-2.5 but y=3/2