SOLUTION: could somebody help, me please? 1)find the center and length of a radius of each circle a) x^2+y^2+8x-12x+43=0 I tried. and got stuck (x^2+8x)+(y^2-12y)=-43 (x^2+8x=43)^2 +

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: could somebody help, me please? 1)find the center and length of a radius of each circle a) x^2+y^2+8x-12x+43=0 I tried. and got stuck (x^2+8x)+(y^2-12y)=-43 (x^2+8x=43)^2 +       Log On


   

Question 156547This question is from textbook college algebra
: could somebody help, me please?
1)find the center and length of a radius of each circle
a) x^2+y^2+8x-12x+43=0
I tried. and got stuck
(x^2+8x)+(y^2-12y)=-43
(x^2+8x=43)^2 + (y^2-12y+12)^2=-43+43+12
then.... This question is from textbook college algebra

Answer by oscargut(2103) About Me  (Show Source):
You can put this solution on YOUR website!
x%5E2%2By%5E2%2B8x-12y%2B43=0
then
x%5E2%2B8x%2By%5E2-12y%2B43=0
then (completing squares)
%28x%5E2%2B8x%2B16%29%2B%28y%5E2-12y%2B36%29-16-36%2B43=0
%28x%2B4%29%5E2%2B%28y-6%29%5E2-9=0
%28x%2B4%29%5E2%2B%28y-6%29%5E2=9
then center is (-4,6) and radius is 3
You can do the exercises using formulas too