SOLUTION: I NEED HELP ON THIS EQUATION COULD YOU HELP ME PLEASE? {{{4X^2+Y^2-8X+6Y-3=0}}} Transform equation by completing the square and graph. {{{(4X^2-8X)+(Y^2+6Y)=3}}} {{{4(X^2+2

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: I NEED HELP ON THIS EQUATION COULD YOU HELP ME PLEASE? {{{4X^2+Y^2-8X+6Y-3=0}}} Transform equation by completing the square and graph. {{{(4X^2-8X)+(Y^2+6Y)=3}}} {{{4(X^2+2      Log On


   

Question 135569: I NEED HELP ON THIS EQUATION COULD YOU HELP ME PLEASE?
4X%5E2%2BY%5E2-8X%2B6Y-3=0
Transform equation by completing the square and graph.
%284X%5E2-8X%29%2B%28Y%5E2%2B6Y%29=3
4%28X%5E2%2B2X%2B1%29%2B%28Y%5E2%2B6Y%2B9%29=3%2B4%2B9
4%28X-1%29%5E2%2B%28Y%2B3%29%5E2=16
WHAT DO I DO AFTERWARDS?
Answer by vleith(2983) About Me  (Show Source):
You can put this solution on YOUR website!
(4X^2-8X)+(Y^2+6Y)=3
4(X^2-2X+1)+(Y^2+6Y+9)=3+4+9
4(X-1)^2+(Y+3)^2=16
%28X-1%29%5E2%2B%28Y%2B3%29%5E2=4
That is i the form of a circle with radius 4, centered at (1,-3)