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Question 131501: Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function, and graph the function.
f(x) = -2x^2+2x+4
The x-Coordinate of the vertex is:
The y-coordinate of the vertex is:
The equation of the line of symmetry is x =
The maximum/minimum of f(x) is
The value, f(1/2) = 17/2 is the minimum or maximum?
Answer by solver91311(24713)   (Show Source):
You can put this solution on YOUR website! The x-coordinate of the vertex of a parabola in the form  is given by  .
The y-coordinate is then  .
The line of symmetry passes through the vertex, so the equation is  .
The maximum or minimum is the value of the function at . Whether it is a maximum or minimum depends on whether the parabola opens up or down. If it is concave up (makes a valley rather than a hill), the point is a minimum, otherwise it is a maximum. You can tell which way the parabola opens by the sign on the lead coefficient. if  , it is concave down, if  , it is concave up, and, of course, if  you don't have a parabola at all.
Let's look at your specific problem:
First thing to note is that , so this is a concave down parabola and the vertex is a maximum.
 , so the x-coordinate of the vertex is  and the equation of the line of symmetry is  .
The value of the function at , denoted for your problem is  (not  !).
So the y-coordinate of the vertex and the maximum value of f is 
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