SOLUTION: The equation of a parabola is C is y=-2x^2+5x. The equation of line L is y-4x+1=0. a)find the intercepts of C with the axes. b) find the line of symmetry and the vertex of C. c) fi
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-> SOLUTION: The equation of a parabola is C is y=-2x^2+5x. The equation of line L is y-4x+1=0. a)find the intercepts of C with the axes. b) find the line of symmetry and the vertex of C. c) fi
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Question 1185687: The equation of a parabola is C is y=-2x^2+5x. The equation of line L is y-4x+1=0. a)find the intercepts of C with the axes. b) find the line of symmetry and the vertex of C. c) find the coordinates of the points of intersection of C and L algebraically. d) sketch C and L on same diagram. Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! The equation of a parabola is C is y=-2x^2+5x. The equation of line L is y-4x+1=0. a)find the intercepts of C with the axes.
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At the y-int, x =0
---> y = 0 is the y-int
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At the x-int, y = 0
x = 0
x = 5/2
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b) find the line of symmetry and the vertex of C. c) find the coordinates of the points of intersection of C and L algebraically. d) sketch C and L on same diagram.
