SOLUTION: A pebble is tossed into the air from the top of a cliff. Its path is modeled by the equation y=−16x^2+32x+80. what is the maximum height reached by the pebble?

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: A pebble is tossed into the air from the top of a cliff. Its path is modeled by the equation y=−16x^2+32x+80. what is the maximum height reached by the pebble?      Log On


   

Question 1170037: A pebble is tossed into the air from the top of a cliff. Its path is modeled by the equation y=−16x^2+32x+80.
what is the maximum height reached by the pebble?
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
y=−16x^2+32x+80.
maximum height is the vertex
vertex x value is -b/2a or -32/-32=x=1 second
y(1)=-16+32+80=96 units
graph%28300%2C300%2C-5%2C5%2C-20%2C110%2C96%2C-16x%5E2%2B32x%2B80%29